Math, asked by Mathematics11, 1 year ago

plz answer this Question .It is very important for me

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Answered by allysia
2
Given that :
QPR is a right angled triangle.
PM is perpendicular on QR


Let angle PRQ be x
Then, angle MPR must equal 180-(90+x)
= 90-x
[As third angle of triangle = 180 - sum of other two angle]


So angle MPR = 90-x


angel RPQ = 90°
If PMR = 90°-x
Then angle QPM = 90 -(PMR)
= 90-(90°-x)
= x
So, angle QPM = x = angle QRP
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