Question

plz answer this question, it's very important please.

Express sin 76° + cos 63° in terms of trigonometric ratios of angles between 0° and 45°
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Answer 1

Answer:

sin 76° + cos 63

sin(90°-14°)+cos(90°-27°)

ie.,cos14°+sin27°

Answer 2

Answer:

sin 76° + cos 63°

We known that

90 - 76 = 14

And

90 - 63 = 27

Therefore,

sin ( 90 - 14 ) + cos ( 90 - 27)

= cos14 + sin 27

Hence the required value is cos 14° + sin 27°

Identity used

cos ( 90 - A ) = sin A

sin ( 90 - A ) = cos A