Question

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The dimensions of a rectangular field are 15m by 12m.A pit 7.5m long 6m wide and 1.5m deep is dig at one corner of the field. The soil removed is evenly spread over remaining area of the field. Calculate the rise in level of field ​

Answer 1

Answer:

Given, Dimension of the field = 15 m × 12 m

Dimension of the pit = 8 m × 2.5m × 2m

Volume of earth removed from the pit = 8m × 2.5 m × 2 m = 40 m3

Area of the remaining field

= Area of the field – Area of the pit

= 15 m × 12 m – 8 m × 2.5 m

= 160 m2

Since, the earth removed is evenly spread over the remaining area of the field.

∴ Increase in level of remaining field × Area of remaining field  = Volume of earth removed from the pit

Increase in level of remaining field = 40/160 =0.25m

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Answer 2

Dimensions of a field:

Length (L)=15 m,

Breadth (B)=12 m,

Dimensions of the Pit:

length (l)= 7.5 m,

width (b)=6 m,

depth (h)=1.5 m,

According to the problem given,

If the pit is dug at one corner of the field and earth removed is evenly spread over the remaining area of the field.

Now,

Area of the remaining field

= Area of the field - base area of the pit

= LB - lb

= 15 × 12 - 7.5 × 6

= 180 m² - 45 m²

= 135 m²

let rise in the level in the remaining field

= volume of the pit / area of the remaining field

= 7.5×6×1.5/135m²

= 0.5m

therefore,

rise in the level in the remaining field

= 0.5m