Question

plz answer this question my boards are coming (DAV Board)
plz 8th class sum
worth 40 points

The dimensions of a rectangular field are 15m by 12m.A pit 7.5m long 6m wide and 1.5m deep is dig at one corner of the field. The soil removed is evenly spread over remaining area of the field. Calculate the rise in level of field ​

Answer 1

ʀɪsᴇ ɪɴ ᴛʜᴇ ʟᴇᴠᴇʟ ɪɴ ᴛʜᴇ

ʀᴇᴍᴀɪɴɪɴɢ ғɪᴇʟᴅ = 0.5 ᴍ

ᴅɪᴍᴇɴsɪᴏɴs ᴏғ ғɪᴇʟᴅ :-

ʟ = 15ᴍ , ʙ = 12ᴍ

ᴅɪᴍᴇɴsɪᴏɴ ᴏғ ᴘɪᴛ :-

ʟ = 7.5ᴍ , ʙ = 6ᴍ , ʜ = 1.5ᴍ

ɪғ ᴛʜᴇ ᴘɪᴛ ɪs ᴅɪɢ ᴀᴛ ᴏɴᴇ ᴄᴏʀɴᴇʀ ᴏғ ᴛʜᴇ ғɪᴇʟᴅ & ᴇᴀʀᴛʜ ʀᴇᴍᴏᴠᴇᴅ ᴇᴠᴇɴʟʏ sᴘʀᴇᴀᴅ ᴏᴠᴇʀ ᴛʜᴇ ʀᴇᴍᴀɪɴɪɴɢ ᴀʀᴇᴀ ᴏғ ᴛʜᴇ ғɪᴇʟᴅ

ᴀʀᴇᴀ ᴏғ ʀᴇᴍᴀɪɴɪɴɢ ғɪᴇʟᴅ =

ᴀʀᴇᴀ ᴏғ ғɪᴇʟᴅ - ʙᴀsᴇ ᴀʀᴇᴀ ᴏғ ᴘɪᴛ

= ʟʙ - ʟʙ

= 15 x 12 - 7.5 x 6

= 180ᴍ² - 45ᴍ²

= 135ᴍ²

ʟᴇᴛ ʀɪsᴇ ɪɴ ᴛʜᴇ ʟᴇᴠᴇʟ ɪɴ

ʀᴇᴀᴍᴀɪɴɪɴɢ ғɪᴇʟᴅ

= ᴠᴏʟᴜᴍᴇ ᴏғ ᴛʜᴇ ғɪᴇʟᴅ /

ᴀʀᴇᴀ ᴏғ ᴛʜᴇ ʀᴇᴍᴀɪɴɢ ғɪᴇʟᴅ

= 7.5 x 6 x 1.5 ᴍ³ / 135 ᴍ²

= 0.5 ᴍ → ᴀɴsᴡᴇʀ

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs :)

ғᴏʟʟᴏᴡ ᴍᴇ ❤❤

Answer 2

Answer:

Rise in the level in the remaining field =0.5m

Step-by-step explanation:

Dimensions of a field:

Length (L)=15 m,

Breadth (B)=12 m,

Dimensions of the Pit:

length (l)= 7.5 m,

width (b)=6 m,

depth (h)=1.5 m,

According to the problem given,

If the pit is dug at one corner of the field and earth removed is evenly spread over the remaining area of the field.

Now,

Area of the remaining field

= Area of the field - base area of the pit

= LB - lb

= 15 × 12 - 7.5 × 6

= 180 m² - 45 m²

= 135 m²

Let rise in the level in the remaining

=volume of the pit

Area of the remaining field

=7.5X6X1.5/15X12

=0.5m

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