Physics, asked by juttuc4, 1 year ago

plz answer this question on fluids.
Two bodies with volumes V and 2V are equalized on a balance. The larger body is then immersed in oil of density r = 0.9 g/cc. What must be the density of the liquid in which the smaller body is simultaneously immersed so as not to disturb the equilibrium of the balance?

Answers

Answered by kvnmurty
38
V1 = V
V2 = 2 V
They have same mass.  Hence their densities are :
M1 = M2      and    d2 = 1/2 * d1

M2 is immersed in oil of density 0.9 g/cc
Buoyancy force on the larger body M2 :  V2 * 0.9 * g 

let the density of the liquid in which the smaller body M1 is immersed be  d g/cc
Buoyancy force on the smaller body M1 :  V1 * d * g

   for the balance to remain at equilibrium:   V2 * 0.9 * g = V1 * d * g
           d = 0.9 V2 / V1 = 0.9 * 2 V/ V = 1.8 g/cc


Answered by sarivuselvi
2

Explanation:

here you go thank you

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