Question

Plz answer this question plz
Chapter-perimeter and area
Plz answer Q6,7,8

Answer 1

Answer:

Q6.length(l) of lawn = 50m

breadth(b)of lawn = 36m

width of path = 2m

so the,

length(L) of outer rectangle = 50+2+2 = 54m

breadth(B) of outer rectangle = 36+2+2 = 40m

Area of path = Area of outer rectangle - Area of inner lawn

= L×B - l×b

= 54×40 - 50×36

= 2160 - 1800

=360m^2

Cost of levelling path = 360×3.25

=Rs.1170

Q7.Solution :-

Total length of the painting including the margin = 40 cm

Total width of the painting including the margin = 28 cm

Area of the painting including the margin = 40*28

Area of the painting including the margin = 1120 sq cm

Length of the painting without the margin = 40 - (2 + 2)

= 40 - 4

= 36 cm

Width of the painting without the margin = 28 - (2 + 2)

= 28 - 4

= 24 cm

Area of the painting without the margin = 36*24

Area of the painting without the margin = 864 sq cm

Area of the margin = Area of the painting including the margin - Area of the painting without the margin

⇒ 1120 - 864

= 256 sq cm

So, the total area of the margin is 256 sq cm

Q8.Each side of flower bed =3.8 m

Area =3.8×3.8sq.m

Area of flower bed before extension =14.44 sq m

If it is extended by digging a strip of 50 cm wide all around it, then the new side will be =3.8+1.0=4.8 m

Area of the flower bed after extension =4.8×4.8

Area of enlarged flower bed =23.04 sq m

Increase in the area of flower bed =23.04−14.44=8.6 sq m.