Question

plz answer this question plz step

Answer 1

rationalize all the terms

as
=> 6/(2√3-√6)
= 6(2√3+√6)/(12-6)
= 2√3+√6


=> √6/(√3+√2)
= √6(√3-√2)
= 3√2-2√3


=> 4√3/(√6-√2)
= 4√3(√6+√2)/4
= 3√2 + √6



so
(2√3+√6)+(3√2-2√3)-(3√2+√6)

= 0


hope it helps you
@di

Answer 2

Here.... Hope it helps