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IN ABC AND EDC TRIANGLE
ANGLE 2=ANGLE 6 (VERTICALLY OPPOSITE ANGLES)
BC=CD (GIVEN EQUAL)
ANGLE 3= ANGLE 5 (ALTERNATE INTERIOR ANGLES)
HENCE PROVED, ∆ABC=∆EDC
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Answer:
yes
Step-by-step explanation:
bc=cd (given)
angle 2 =angle 6 (verticaly opposite )
angle 3=angle 5 (given)
hence triangle abc =triangle edc by asa
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