plz answer this question quickly
Attachments:
Answers
Answered by
1
Hi there!
Given a + b + c = 0
⇒ a³ + b³ + c³ = 3abc ----(i)
Consider,
L.H.S = (a²/bc) + (b²/ca) + (c²/ab)
(a³ + b³ + c³)/abc
3abc/abc = 3 [from Eqn. (i)] = R.H.S
Cheers!
Given a + b + c = 0
⇒ a³ + b³ + c³ = 3abc ----(i)
Consider,
L.H.S = (a²/bc) + (b²/ca) + (c²/ab)
(a³ + b³ + c³)/abc
3abc/abc = 3 [from Eqn. (i)] = R.H.S
Cheers!
Similar questions