plz answer this question right now plz its urgent.
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Hey there !
Thanks for the question !
Here's the answer !
Q1. Given that ABCD is a parallelogram.
Properties of Parallelogram :
- They have equal opposite angles.
- They have adjacent supplementary angles
This implies that, ∠ A = ∠ C and ∠ A + ∠ B = 180°.
Given that, ∠ A = 72°
⇒ ∠ C = 72°
Also, ∠ B = 180° - ∠ A
⇒ ∠ B = 180° - 72°
⇒ ∠ B = 108° = ∠ D.
So the measures are: ∠ B = ∠ D = 108° ; ∠C = 72°.
___________________________________________________________
Q2. Consider Δ BDC
∠ A = ∠ C ( Opposite Angle of Parallelogram )
=> ∠ C = 80°
Now applying Angle Sum property for Δ BDC, we get,
=> 60 + 80 + ∠ CDB = 180°
=> 140 + ∠ CDB = 180°
=> ∠ CDB = 180 - 140 = 40°
Considering AB ║ DC, BD as the transversal we get that,
∠ CBD = ∠ ADB ( Alternate Angles )
=> ∠ ADB = 60°.
Hope my answer helped !
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