plz answer this question tomorrow is my exam
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hope it will be helpful for you and God bless you in your exam
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kevenmitneck:
nice answer mam or didi
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Step-by-step explanation:
Using LHS ,
Multiply numerator and denominator by ( cosec theta - cot theta ).
Now ,
sin(cosec -cot)/(cosec+cot)(cosec-cot)=( sin•cosec -sin•cot )/cosec^2 - cot^2 = 1-cos.
Using RHS ,
Multiply second term with (-cosec-cot).
Now , 2+ sin•(-cosec) - cot •sin/(cosec^2 -cot^2)= 2+( -1-cos)/1= 2-1+cos=1+cos
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