Question

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Answer 1

Answer:

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Answer 2

GiveN :-

• Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 50 seconds.

• Then turns around and jogs 100 m back to point C in another 1 minute.

TO FinD :-

The average speed and velocities in jogging :

(a) from A to B and

(b) fromA to C

AcknowledgemenT :-

• Average speed = Total distance covered/Total time taken

• Average velocity = Overall displacement/Total time taken

Distance is the total length of the path covered between the initial position and the final position.

Displacement is the shortest length of the path between the initial position and the final position.

SolutioN :-

CASE 1

Here, no change in direction occurs. So,

Distance = Displacement = 300 m

Time taken to cover 300 m = 2 mins 50 secs = 120 + 50 = 170 secs

Average speed = Total distance covered/Total time taken

→Average speed = 300/170

→Average speed = 30/17 m/s

$\rule{150}2$

Average velocity = Overall displacement/Total time taken

→Average velocity = 300/170

→Average velocity = 30/17 m/s

$\underline{\rule{200}2}$

CASE 2

Total distance travelled = 300 + 100 = 400 m

Overall displacement = 300 - 100 = 200 m

(As the direction is opposite towards C)

Time taken = 170 s + 1 min = 170 + 60 = 230 s

Average speed = Total distance covered/Total time taken

→Average speed = 400/230

→Average speed = 40/23 m/s

$\rule{150}2$

Average velocity = Overall displacement/Total time taken

→Average velocity = 200/230

→Average velocity = 20/23 m/s