plz answer this question urgent
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9(3y+2)(5y-7)/3(5y-7) {Cancelling (5y-7) in numerator and denominator}
9(3y+2)/3 {Cancelling 9 in numerator by 3 in denominator}
3(3y+2)
9y+6
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hlo dear your answer is here
9y+6
Step-by-step explanation:
divide 9 into two parts (3x3) and multiply individually with both components [(5y-7) and (3y+2)]
then divide the whole term with 3(5y-7)
like the above image
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