Math, asked by babitadevi030380, 4 months ago

plz answer this question urgent ​

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Answered by adityak280505
2

9(3y+2)(5y-7)/3(5y-7) {Cancelling (5y-7) in numerator and denominator}

9(3y+2)/3 {Cancelling 9 in numerator by 3 in denominator}

3(3y+2)

9y+6

Answered by vedant129099
1

Answer:

hlo dear your answer is here

9y+6

Step-by-step explanation:

divide 9 into two parts (3x3) and multiply individually with both components [(5y-7) and (3y+2)]

then divide the whole term with 3(5y-7)

like the above image

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