Plz answer this question with formula I will mark as brainliest
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ACCORDING TO GIVEN CONDITION,
LENGTH=75M AND BREADTH=50M
THEREFORE,PERIMETER OF HOUSE =2(75+50)
=2(125)
= 250 M
NOW, SHE HAS TO PLANT TREES AT THE DISTANCE OF 3 M APART,SO
NO. OF TREES=TOTAL PERIMETER/ DISTANCE BETWEEN TREES
250/3 =83.3
SO 83 PLANTS WILL BE PLANTED
hope it helps brainlist
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