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Area of the shaded region ABC is simply the area of the triangle OABC minus the area of circular sector OAC. ΔOAB seems to be a right angle triangle, with ∠A = 90°. AB seems to be the tangent.
OA = radius = r.
AB/OA = Tan θ°
So AB = OA Tanθ° = r Tan θ°.
ar(ΔOAB) = 1/2 * OA * AB
= 1/2 * r² * Tan θ°
ar(Sector OAB) = π r² * (θ°/360°) , as θ is in degrees.
= 1/2 * r² θ° * (π/180°)
Shaded region = 1/2 * r² * [Tanθ° - π θ°/180°]
OA = radius = r.
AB/OA = Tan θ°
So AB = OA Tanθ° = r Tan θ°.
ar(ΔOAB) = 1/2 * OA * AB
= 1/2 * r² * Tan θ°
ar(Sector OAB) = π r² * (θ°/360°) , as θ is in degrees.
= 1/2 * r² θ° * (π/180°)
Shaded region = 1/2 * r² * [Tanθ° - π θ°/180°]
tnwramit1:
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This is ur answer hope it will help u
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