Math, asked by HridayAg0102, 1 year ago

Plz answer this question. .............. WITH FULL SOLUTION. ...NO SHORTCUTS....AND NO GUESSING.

ar \: of \: shaded \: region =  \frac{ {r}^{2} }{2}  \times ( \tan(theta) -  \frac{\pi \times theta}{180})

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Answers

Answered by kvnmurty
2
    Area of the shaded region ABC is simply the area of the triangle OABC minus the area of circular sector OAC.  ΔOAB seems to be a right angle triangle, with ∠A = 90°.  AB seems to be the tangent.

  OA = radius = r. 

    AB/OA = Tan θ°
So  AB = OA Tanθ° = r Tan θ°.

ar(ΔOAB) = 1/2 * OA * AB
                = 1/2 * r² * Tan θ°

ar(Sector OAB) = π r² * (θ°/360°) ,         as θ is in degrees.
                = 1/2 * r² θ° * (π/180°) 

Shaded region = 1/2 * r² * [Tanθ° - π θ°/180°]


tnwramit1: ok
HridayAg0102: me too
tnwramit1: let me check
tnwramit1: r²/2 common out
HridayAg0102: I m saying about
HridayAg0102: that sector one
HridayAg0102: pi × r square × theta / 360* = r square / 2 × pi/180
HridayAg0102: how it came??
tnwramit1: wait I m answer whole question
HridayAg0102: ok
Answered by tnwramit1
2
This is ur answer hope it will help u
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HridayAg0102: ok got that
HridayAg0102: thx for help
tnwramit1: ok
tnwramit1: np
HridayAg0102: hi
tnwramit1: hii
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