Math, asked by basumataryanup242, 7 months ago

plz answer this questions .....plz​

Attachments:

Answers

Answered by abhijeetgorai836
1

Step-by-step explanation:

4- 130°

5-110°

6-85°

please Mark it as brainliest answer

Answered by Anonymous
1

Step-by-step explanation:

(i) Sum of angles of quadrilateral = 360°

    Let the 2 angles be 'a' and 'b'. (Let them in your figure.)

Sum of angles = 360°

x + a + 140° + b = 360°

Let us find values of 'a' and 'b'.

(As 'a' and 140° is a linear pair so their sum would be 180°)

a + 130° = 180°

a = 180° - 130°

a = 50°

('b' and 130° is linear pair, so their sum = 180°)

b + 140° = 180°

b = 180° - 140°

b = 40°

Now let us find value of x,

Sum of angles = 360°

x + a + 140° + b = 360

x + 50° + 140° + 40° = 360°

x + 230° = 360°

x = 360° - 230°

x = 130°

ANSWER is = x = 130°

_________________________________________________

(ii) Find x.

In your figure, Let the 4 interior angles be a, b, c, d.

Let us find 'a' , 'b' , 'c' , 'd'.

a + 120° = 180° (as it is a linear pair)

a = 180° - 120°

a = 60°

b + 50° = 180° (as it is a linear pair)

b =  180° - 50° = 130°

c + 80° = 180°

c = 180° - 80° = 100°

d = 180° - x

Sum of all angles of quadrilateral = 360°

a + b + c + d = 360°

60° + 130° + 100° + 180°-x = 360°

470° - x = 360°

470° = 360° + x

x = 470° - 360°

ANSWER is ; x = 110°

Verifying -

a + b + c+ d = 360°

60° + 130°+ 100° + 180° - x = 360°

60° + 130° + 100° + 180° - 110° = 360°

470° - 110° = 360°

360° = 360°

LHS = RHS

Hence , our answer is correct.

_________________________________________________

(iii) Let the 3 interior angles which are not given be a, b, c in your figure.

a = 180° - 55° = 125° ( As it is a linear pair)

b = 180° - 130° = 50°

c = 180° - y

The other angle is given which is of 90°

Sum of angles = 360°

a + b + c + 90 = 360

125 + 50 + 180 - y + 90 = 360

445 - y = 360

445 = 360 + y

y = 445 - 360

ANSWER = y = 85

_________________________________________________

HOPE IT HELPS..................

PLEASE MARK ME BRAINLIEST.................

Similar questions