plz answer this someone. with all steps
question no 13 plzz
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de || Ab
since,
angle cde = angle dab .....1
angle ced = angle eba......2
in triangle cde and triangle cab ,
by using eq. 1 and 2
tri. cde ~ tri. cab ...
since from this
ar. (tri.abc)/ ar.( tri. cde) = ac^2 / cd^2
as given,
ar. ◇ abc / ◇ abc - ◇dabe = (ad + dc)^2 / dc^2
ar(◇abc) / ar ◇ abc -40 = 3dc ^2 / dc^2
ar. ◇ abc / ar. ◇ abc - 40 = 3
ar. abc = 3. ar abc - 120
2. ar abc = 120
ar. abc = 60 cm^2
HERE URS ANSWER STEP BY STEP...
HOPE HELPS U
since,
angle cde = angle dab .....1
angle ced = angle eba......2
in triangle cde and triangle cab ,
by using eq. 1 and 2
tri. cde ~ tri. cab ...
since from this
ar. (tri.abc)/ ar.( tri. cde) = ac^2 / cd^2
as given,
ar. ◇ abc / ◇ abc - ◇dabe = (ad + dc)^2 / dc^2
ar(◇abc) / ar ◇ abc -40 = 3dc ^2 / dc^2
ar. ◇ abc / ar. ◇ abc - 40 = 3
ar. abc = 3. ar abc - 120
2. ar abc = 120
ar. abc = 60 cm^2
HERE URS ANSWER STEP BY STEP...
HOPE HELPS U
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the ans is 5 cm² if you want a solⁿ comment in this ans i will send you
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