plz answer this three question plz
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Step-by-step explanation:
(2x+3y)^3
= (2x)^3+ 3(2x)^2× 3y + 3×2x(3y)^2 + (3y)^3
= 8x^3 + 36x^2× y + 54xy^2+ 27y^3
(3x-2y)^3
=(3x)^3 -3(3x)^2 × 2y + 3× 3x(2y)^2 + (2y)^3
= 27x^3 -54x^2 y + 36xy^2 + 8y^3
(1/3x- 2/5y)^3
= (1/3x)^3 - 3(1/3x)^2 × (2/5y) + 3 (1/3x)(2/5y)^2 - (2/5y)^3
= (1/9x^2) - (6/45x^2 y) + (12/25xy^2) - (8/125y^3)
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