plz answer this three questions
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are you narayana school and me too
6)for first we see 12π,12π12π are in parallel so 1/12+1/12+1/12=1/4
so now the other 12π on upside is in series with this three resistors so 1/4+12=49/4= approx of 12.25
now the current=12.25/3 is approx 4
6)for first we see 12π,12π12π are in parallel so 1/12+1/12+1/12=1/4
so now the other 12π on upside is in series with this three resistors so 1/4+12=49/4= approx of 12.25
now the current=12.25/3 is approx 4
chandrika025:
say me clearly
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