Question

plz answer this.... thx​

Answer 1

$\frac{6}{3 \sqrt{2} - 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3} \\ \frac{6}{3 \sqrt{2} - 2 \sqrt{3} } \times \frac{3 \sqrt{2} + 2 \sqrt{3} }{3 \sqrt{2} + 2 \sqrt{3} } = 3 \sqrt{2} - a \sqrt{3} \\ \frac{18 \sqrt{2} + 12 \sqrt{3} }{(3 \sqrt{2}) ^{2} - (2 \sqrt{3}) ^{2} } = 3 \sqrt{2} - a \sqrt{3} \\ \frac{18 \sqrt{2} + 12 \sqrt{3} }{18 - 12} = 3 \sqrt{2} - a \sqrt{3} \\ \frac{6(3 \sqrt{2} + 2 \sqrt{3} )}{6} = 3 \sqrt{2} - a \sqrt{3} \\ 3 \sqrt{2} + 2 \sqrt{3} = 3 \sqrt{2} - a \sqrt{3}$

Comparing the both sides, we get

a=-2