Question

plz answer this

trigonometry class 10.........​

Answer 1

Answer:

$\frac{(1 + cos) {}^{2} }{sin {}^{2}}$

$\frac{(1 + \cos)(1 + \cos) }{(1 - \cos) {}^{2} }$

$\frac{(1 + \cos)(1 + \cos)}{(1 + \cos)(1 - \cos)}$

$\frac{(1 + \cos)}{(1 - \cos)}$

Answer 2

${\large\bf{\mid{\overline{\underline{To\:Prove:-}}}\mid}}$

$\blue{\sf(\dfrac{1 + cos \theta}{sin\theta}) ^{2} = \dfrac{1 + cos\theta}{1 - cos\theta}}$

$\large\star{\underline{\tt{\red{Answer}}}}\star$

$\bf \: solving \: \red{LHS} \: we \: get : - -$

$\sf(\dfrac{1 + cos \theta}{sin\theta}) ^{2} \\ \\ \red\leadsto \: \sf\dfrac{(1 + cos \theta)^{2} }{(sin^{2} \theta) } \\ \\ \bf \: now \: we \: know \: that \\ \\ \: \green{\large\boxed{\sf \: sin^{2}\theta = 1 - cos^{2}\theta}} \\ \\ \pink{\large\boxed{\sf \: {x}^{2} - {y}^{2} = (x + y)(x - y)}} \\ \\ \bf putting \: both \: in \: denominator \: we \: get \\ \\ \red\leadsto \: \sf\dfrac{(1 + cos \theta)^{ \cancel2} }{ \cancel{(1 + cos \theta)}(1 - cos \theta)} \\ \\ \red\leadsto \: \sf \: \purple{\dfrac{(1+cos \theta)}{(1 - cos \theta)}} \\ \\ \pink{\large\boxed{\boxed{\bold{= RHS}}}} \\ \\ \\ \LARGE\red{\boxed{\tt\blue{Hence}\purple{,}\green {Proved}}}$

_____________________________________

#answerwithquality

#BAL