Question

plz answer this two questions..
plz do fast..
who know the explanation for answers can only solve these.. plzz​

Answer 1

ANSWER:

X2-4X+1=0

=X2-4X=-1

=X(X-4)=-1=X-4=-1/X--- 1

=X+1/X-4--- 2

from equation 1 x-4=-1/x

=x+1/x=4

cube on both sides

(x+1/x)3=(4)3

=x3+1/x3+3*x*1/x(x+1/x)=64

=x3+1/x3+3(4)=64(put eq 2)

=x3+1/x3+12=64

=x3+1/x3=52

So, this is your first answer

Answer 2

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X2-4X+1=0

=X2-4X=-1

=X(X-4)=-1=X-4=-1/X--- 1

=X+1/X-4--- 2

from equation 1 x-4=-1/x

=x+1/x=4

cube on both sides

(x+1/x)3=(4)3

=x3+1/x3+3*x*1/x(x+1/x)=64

=x3+1/x3+3(4)=64(put eq 2)

=x3+1/x3+12=64

=x3+1/x3=52

So, this is your first answer

Step-by-step explanation: