Question

plz answer thse all questions...step by step..class 8...and plz don't spam​

Answer 1

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$\green\implies$Given 3380,

Resolve 3380 into prime factors, we get

3380=2×2×5×13×13=(22×132×5)

Now to get perfect square we have to multiply the above equation by 5

Then we get, 

3380=2×2×5×5×13×13

New number =(4×25×169)

=(22×52×132)

Taking squares as common from the above equation we get

∴ New number =(2×5×13)²

=(130)²

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Answer 2

Explanation:

3380=2×2×5×5×13×13

New number =(4×25×169)

=(22×52×132)

Taking squares as common from the above equation we get

∴ New number =(2×5×13)²

=(130)²