Question

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Answer 1

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No. of moles of ethanol in 138 g of ethanol =    $\frac{138}{46}$ = 3 moles

No. of moles of water in 126 g of water =   $\frac{126}{18}$ =  moles

Mole fraction = $\frac{No.\:\:of\:\:moles\:\:of\:\: compound\:\:A}{No.\:\:of\:\:moles\:\:of\:\: compound\:\:A+No.\:\:of\:\:moles\:\:of\:\: compound\:\:B}$

Mole fraction of water = $\frac{7}{7+3}$ = $\frac{7}{10}$ = 0.7

Mole fraction of ethanol = $\frac{3}{7+3}$ = $\frac{3}{10}$ = 0.3