Math, asked by ydtodkar25, 10 months ago

plz answer to this question......​

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Answered by kutty02
1

Answer:

sinAcosA

Step-by-step explanation:

let theta be A

tanA/(1+tan^2A)^2+

cotA/(1+cot^2A)^2 tanA/sec^4 + cotA/cosec^4

(sinA/cosA)/(1/cos^4A)

+(cosA/sinA)/(1/sin^4A)

by cancelling we get

sinA cos^3A+ cosAsin^3

sinAcosA(cos^2A+sin^2A)

sinAcosA (1)

=sinAcosA

this is the answer

be blessed

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