plz answer to this question......
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Answer:
sinAcosA
Step-by-step explanation:
let theta be A
tanA/(1+tan^2A)^2+
cotA/(1+cot^2A)^2 tanA/sec^4 + cotA/cosec^4
(sinA/cosA)/(1/cos^4A)
+(cosA/sinA)/(1/sin^4A)
by cancelling we get
sinA cos^3A+ cosAsin^3
sinAcosA(cos^2A+sin^2A)
sinAcosA (1)
=sinAcosA
this is the answer
be blessed
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