plz answer tomorrow is my exam
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Answer is Option A Hope it helps
Explanation:- a² + b² + c² - ab - bc - ac
= ( 2a² + 2b² + 2c² - 2ab - 2bc - 2ac )/2
Rearrange the above expression
( a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2ac )/2
=[ (a-b)² + (b-c)² + (c-a)² ]/2
Since the expression is a sum of 3 squares it cannot be negative (assuming a,b,c to be real). Therefore the expression is greater than or equal to 0. (0 when a=b=c)
Explanation:- a² + b² + c² - ab - bc - ac
= ( 2a² + 2b² + 2c² - 2ab - 2bc - 2ac )/2
Rearrange the above expression
( a² + b² - 2ab + b² + c² - 2bc + a² + c² - 2ac )/2
=[ (a-b)² + (b-c)² + (c-a)² ]/2
Since the expression is a sum of 3 squares it cannot be negative (assuming a,b,c to be real). Therefore the expression is greater than or equal to 0. (0 when a=b=c)
mujhe pata hai
can u explain it
???
what
options a
wait
I also know that how to explain
kaha cale gaye
cool guy
now u got it..
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