Question

Plz answer urgent
Plz plz​

Answer 1

Answer:

Refer to the above answer

Step-by-step explanation:

Hope this help you

Answer 2

ANSWER :- a = 5 , b = 2

$\bf\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = a \: + b \sqrt{6}$

$\bf\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} } = \frac{( \sqrt{3} + \sqrt{2}) \times ( \sqrt{3} + \sqrt{2}) }{( \sqrt{3} - \sqrt{2} ) \times ( \sqrt{3} + \sqrt{2} }$

$\bf\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{( \sqrt{3} + \sqrt{2}) {}^{2} }{( \sqrt{3} ) {}^{2} - ( \sqrt{2} ) {}^{2} }$

$\bf\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{( \sqrt{ 3}) {}^{2} + 2. \sqrt{3}. \sqrt{2} + ( \sqrt{2}) {}^{2} }{3 - 2}$

$\bf\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3 + 2 + 2. \sqrt{3}. \sqrt{2} }{1}$

$\bf\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 + 2 \sqrt{6}$

$\bf5 + 2 \sqrt{6} = a + b \sqrt{6}$

$\bf a \: = 5$

$\bf b \: = 2$