Question

Plz answer urgently.

Answer 1

Answer:

$\sqrt{2} x + \sqrt{18} y = 0...1 \\ \sqrt{3} x + \sqrt{45} y= 0 ...2\\ from \: 1 \:a nd \: 2 \: \: \\ \sqrt{2} x + \sqrt{18} y = \sqrt{3} x + \sqrt{45} y \\ \sqrt{2} x - \sqrt{3} x = \sqrt{45} y - \sqrt{18}y \\ x( \sqrt{2} - \sqrt{3} ) = y( \sqrt{45} - \sqrt{18} ) \\ \frac{x}{y} = \frac{ \sqrt{45} - \sqrt{18} }{ \sqrt{2} - \sqrt{3} }$