plz answer with explaination
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Solution :
• 1st cylindrical shape :
Height = 49 cm
Diameter of base = 16 cm
Radius of base = 16/2 cm = 8 cm
∴ volume (V₁) = π * 8² * 49 cm³
• 2nd cylindrical shape :
Height = 35 cm
Diameter of base = 14 cm
Radius of base = 14/2 cm = 7 cm
∴ volume (V₂) = π * 7² * 35 cm²
• Final cylindrical shape :
Height = 56 cm
Radius of base = r cm (say)
∴ volume (V) = π * radius² * 56
ATQ,
V = V₁ + V₂
or, π * r² * 56 = (π * 8² * 49) + (π * 7² * 35)
or, 56 r² = (8² * 49) + (7² * 35)
or, 8 r² = (8² * 7) + (7² * 5)
or, 8 r² = 448 + 245
or, 8 r² = 693
or, r² = 86.625
or, r ≈ 9.31
∴ the radius of the base of the new cylindrical shape is 9.31 cm and thus its diameter is (2 * 9.31) cm, i.e. 18.62 cm
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