Question

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Answer 1

Answer:

2 - 100cm, 3 - 660cm, 4 - 106 cm, 5 - 9.6 km

Step-by-step explanation:

In all cases, the perimeter is required.

We know the formula for the perimeter of a rectangle: 2(l+b)

2. l = 40cm, b = 10cm

Perimeter: 2(40+10)  = 2(50)

∴Perimeter: 100 cm

So the length of tape required is 100 cm.

3. l = 2.25 m, b = 1.5m

Perimeter: 2(2.25+1.5) = 2(3.3)

∴Perimeter: 6.6 m or 660 cm

4. l = 32cm, b= 21 cm

Perimeter: 2(32+21) = 2(53)

∴Perimeter: 106 cm

5. l = 0.7 km, b= 0.5 km

Perimeter: 2(0.7+0.5) = 2(1.2)

∴Perimeter: 2.4 km

It is given that each side is fenced with four rows of wire.

So, the length of wire needed is 4*Perimeter = 4*2.4

∴The length of wire needed is 9.6 km = 9600 m

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Answer 2

Step-by-step explanation:

FORMULA = 2(l+ b)

2. l=40 cm b = 10 cm

perimeter = 2( 40 +10) = 2 (50)

perimeter = 100

so length required is = 100 cm.

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3. l = 2.25 m b = 1.5 m

perimeter = 2 (2.25 +1.5 ) = 2 ( 3.3)

perimeter = 6.6 or 660

so the required length is = 6.6 Or 660.

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l = 32 cm b = 21 cm

perimeter = 2(32 + 21 ) = 2 ( 53 )

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l = 0.7 cm b = 0.5 km

perimeter = 2 ( 0.7 + 0.5 ) = 2 ( 2.2)

perimeter = 2.4 km

5. it is given that each side is fenced with four rows of wire

so the required length is = 4* perimeter

= 4*2.24

= 9.6 km

= 9600 m

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answer : 2. 100 cm 3. 6.6 or 660 4. 9600 m

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