Question

plz answera uniform meter rule balances horizontally on a knife edge placed at 42cm mark when a weight of 40 gf is sudpended from one end 1) draw a diagram of the arrangement 2)what is the weight of the ruler?​

Answer 1

Answer:

(i) Weight mg (W) of rule produces an anti-clockwise moment about the knife edge O. In order to balance it, 20gf must be suspended at the end B to produce clockwise moment about the knife edge O. (ii) From the principle of moments, Anticlockwise moment = Clockwise moment W × (58-50) = 20gf × (100 − 58) W × 8 = 20gf × 42 W = 20gf x 42/8 = 105 gfRead more on Sarthaks.com - https://www.sarthaks.com/142873/uniform-metre-rule-balance-horizontally-knife-edge-placed-mark-when-weight-suspended-from?show=142878#a142878

Step-by-step explanation:

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Answer 2

Answer:

(i) Weight mg (W) of rule produces an anti-clockwise moment about the knife edge O. In order to balance it, 20gf must be suspended at the end B to produce clockwise moment about the knife edge O. (ii) From the principle of moments, Anticlockwise moment = Clockwise moment W × (58-50) = 20gf × (100 − 58) W × 8 = 20gf × 42 W = 20gf x 42/8 = 105 gf