Question

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Answer 1

Your answer is in above attachment..

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Answer 2

Answer:

Let 'r' be the radius of semicircular path.

Here, l = (2πr/2) = πr⇒ r = 1/π

Diameter = 2r = 2l/π

Magnitude of displacement = diameter = 2l/π

Thus, Distance/ Displacement = 1/2l/π = π/2