Question

plz answers kro guys✌✌

Answer 1

Hi there!
Here's the answer:

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¶¶¶ POINTS TO REMEMBER:

¶ SIN = OPPOSITE/HYPOTENUSE

¶ COS = ADJACENT/HYPOTENUSE

¶ TAN = OPPOSITE/ ADJACENT

¶ According to Pythagoras theorem,
HYP² = ADJ² + OPP²

¶ (a+b)² - (a-b)² = 4ab
{ (a² + b² +2ab) - (a² + b² - 2ab)
= a² + b² +2ab - a² - b² + 2ab
= 4ab}

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¶¶¶ SOLUTION:

Taking theta as 'a'

Given,
Sin a = (x² - y²)/(x²+y²)

Here,
Opp = (x² - y²) & Hyp =(x²+y²)

Using Pythagoras theorem, find the other side
Let Adj be 'A'

=> (x²+y²)² = (x²-y²)² + A²

=> A² = (x²+y²)² - (x²-y²)²

=> A² = 4x²y²
{Here, a= x² ; b = y²}

=> A = √ 4x²y²

=> A = 2xy

•°• Adj = 2xy

Adj = 2xy ; Opp = (x² - y²) & Hyp =(x²+y²)

Now, we have all sides
So any trigonometric ratio can be found

(1)

cos a = 2xy/(x²+y²)

(2)

tan a = (x²-y²)/2xy

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Hope it helps

Answer 2

$\boxed{SORRY}$

please try to understand