Question

plz answers the questions​

Answer 1

it is answer of 27 (ii)

Answer:

answer no 26

The theorem of parallel axis states that the moment of inertia of a body about any axis is equal to sum of its moment of inertia about a parallel axis through the centre of mass and the product of the mass of the body and the square of the perpendicular distance between the two axes.

The theorem of perpendicular axes about moment of inertia states that the moment of inertia of a plane lamina about an axis perpendicular to its plane is equal to the sum of its moments of inertia about two mutually perpendicular axes in its plane and through the point of intersection of the perpendicular axis and the lamina.

Answer 2

Answer:

We have,

ABCD as the cyclic quadrilateral in which the diagonal AC and BD.

intersect each other at point P.

also, given that,

AB=8cm,

CD=5cm

Now,

In ΔDCA and ΔAPB,

We have

∠DCP=∠ABP

∠CDP=∠PAB

Hence, 

ΔDPC∼ΔAPB (by A.A property)

According to the given question,

arΔAPBarΔDPC=(ABDC)2

⇒24arΔDPC=(85)2

⇒24arΔDPC=6425

⇒arΔDPV=6425×24

arΔDPC=9.375cm2