Math, asked by zohrafatima, 1 year ago

plz answr frndz..plz answer frndz don't ignore it plz ....

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Answered by Anonymous
1
Given,

p = a^2 b^3

q = a^3 b

Prime factors of p = a * a * b * b * b

Prime factors of q = a * a * a * b

H.C.F  = a * a * b  = a^2 * b { Since a and b are prime numbers , so they won't have any common factor. }

L.C.M = a * a * b * a  * b * b = a^3 * b^3.

Now,

H.C.F x L.C.M = a^2 * b * a^3 * b^3 = a^5 * b^4. --- eq.1

Product of numbers = a^2 * b^3 * a^3 * b = a^5 * b^4--- eq,2

From ( 1 ) and ( 2 ) , we get,

H.C.F x L.C.M = Product of numbers.

Verified.

zohrafatima: thanku soo much
zohrafatima: hey listen plz can u do it in note book with using divide method alsoo plz
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