plz answr it
step by step
Attachments:
Answers
Answered by
1
hey mate!!
here's your answer...
(it became so simple if you know the formula)
a³+b³+c³-3abc =(a+b+c)(a²+b²+c²-ab-bc-ca)
now,
a + b + c = 5
ab + bc + ca = 10
so,
(a + b + c)² = a² + b² + c² +2(ab + bc+ca)
(5)² -2×10 = a² + b² + c²
a² + b² + c² =5
so put it in formula :
a³+b³+c³-3abc=(a+b+c)[a²+b²+c²-ab-bc-ca]
=(5)[5-(10)]
=(5)(-5)
=(-25) Answer....
Similar questions