plz answr the question fast i ha ve my test tomorrow
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Given x - y = 7 and x^3 - y^3 = 133.
x^3 - y^3 = 133
(x - y)(x^2 + y^2 + xy) = 133
(7)(x^2 + y^2 + xy - 2xy + 2xy) = 133 ( Add and subtract -2xy)
(7)(x^2 + y^2 - 2xy) + 3xy) = 133
(7)(x - y)^2 + 3xy) = 133
(7)(7)^2 + 3xy) = 133
(7)(49 + 3xy) = 133
343 + 21xy = 133
21xy = 133 - 343
21xy = -210
xy = -10
(ii)
we know that (x - y)^2 = x^2 + y^2 - 2xy
(7)^2 = x^2 + y^2 - 2 * -10
49 = x^2 + y^2 + 20
x^2 + y^2 = 29.
(or)
x^3 - y^3 = (x - y)(x^2 + y^2 + xy)
133 = (7)(x^2 + y^2 + -10)
19 = x^2 + y^2 - 10
x^2 + y^2 = 29.
Hope this helps!
x^3 - y^3 = 133
(x - y)(x^2 + y^2 + xy) = 133
(7)(x^2 + y^2 + xy - 2xy + 2xy) = 133 ( Add and subtract -2xy)
(7)(x^2 + y^2 - 2xy) + 3xy) = 133
(7)(x - y)^2 + 3xy) = 133
(7)(7)^2 + 3xy) = 133
(7)(49 + 3xy) = 133
343 + 21xy = 133
21xy = 133 - 343
21xy = -210
xy = -10
(ii)
we know that (x - y)^2 = x^2 + y^2 - 2xy
(7)^2 = x^2 + y^2 - 2 * -10
49 = x^2 + y^2 + 20
x^2 + y^2 = 29.
(or)
x^3 - y^3 = (x - y)(x^2 + y^2 + xy)
133 = (7)(x^2 + y^2 + -10)
19 = x^2 + y^2 - 10
x^2 + y^2 = 29.
Hope this helps!
siddhartharao77:
:-)
Answered by
0
HI,
Please see the attached file!
Thanks
Please see the attached file!
Thanks
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