Question

plz answr this question​

Answer 1

Given:-

๛A=(3,4)→(x1,y1)

๛B=(-4,-3)→(x2,y2)

$\rule{200}{1}$

To Find:-

✪The Distance of the points?

$\rule{200}{1}$

AnsWer:-

✪Option 3 is Correct.

Explanation:-

▼Using Distance Forumla▼

➜√AB=√(x2-x1)²+(y2-y1)²

•Putting the Values•

➜√AB=√(-4-3)²+(-3-4)²

➜√AB=√(-7)²+(-7)²

➜√AB=√49+49

➜√AB=7+7

☞√AB=14

$\rule{200}{2}$

Answer 2

.....

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QUESTION -

$\sf{ Two \: points \: ( 3 , \: 4 ) \: and \: ( -4 , \: -3 ) \: are \: at }$

$\sf { a \: distance \: from \: each \: other \: }$

$\sf { ( approximate ) \: :- \\ \\ [1] \: 10 \: m \\ \\ [ 2 ] \: 7 \: m }$

$\\ \\ [ 3 ] \: 14 \: m \\ \\ [ 4 ] \: 5 \: m }$

FORMULAE USED -

$Distance \: between \: two \: points \: :- \\ \\ d = \sqrt{ { x_{2} - x_{1} } ^ 2 + { y_ { 2 } - y _ { 1 } } ^ 2 }$

Substuting the required values :

$d = \sqrt{ { ( -4-3 ) } ^ 2 + {( -3-4 ) } ^ 2 } \\ \\ => \sqrt { 2 \times {( -7 ) } ^ 2 } \\ \\ => \sqrt{98} \\ \\ => 9.89 \: m \\ \\ => \approx \: 10 \: m . \: </p><p>.......... [ 1 ]$