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(i) Let A = (0,-2)
B=(3,1)
C=(0,4)
D=(-3,1)
(AB)^2 = (3-0)^2 + (1+2)^2
= 9+9 = 18
AB = √18= 3√2
similary BC = 3√2
CD=3√2
DA=3√2
AB=BC=CD=DA=3√2
Since all sides equal points are vertices of a square
(ii) AB = √20
BC= √80
CD= √20
DA = √80
since Opposite sides equal these points are vertices of a rectangle
B=(3,1)
C=(0,4)
D=(-3,1)
(AB)^2 = (3-0)^2 + (1+2)^2
= 9+9 = 18
AB = √18= 3√2
similary BC = 3√2
CD=3√2
DA=3√2
AB=BC=CD=DA=3√2
Since all sides equal points are vertices of a square
(ii) AB = √20
BC= √80
CD= √20
DA = √80
since Opposite sides equal these points are vertices of a rectangle
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