Question

plz anwer the question its vry urgent

Answer 1

not seen clearly the ques:

Answer 2

p(x)= x2+px+q

g(x)= x+a

x = -a

p(-a)= a2-ap+q=0( 1st equation)

p1(x)=x2+mx+n

p1(-a)=a2-am+n=0 (2nd equation)

on equating 1 and 2,we have

a2-am+n=a2-ap+q

-am+ap=q-n

-a(m-p)=q-n

-a= q-n/m-p

a= n-q/m-p

hence proved