Question

plz anwser the following

Answer 1

Answer:

1 answer will be the option B

Hope it helps you

Answer 2

Step-by-step explanation:

•Rewrite it in the form $\tt{a}^{2}-2ab+{b}^{2}$

, where $\tt a={x}^{2}$and b=4.

$\tt{({x}^{2})}^{2}-2({x}^{2})(4)+{4}^{2}$

•Use Square of Difference: $\tt{(a-b)}^{2}={a}^{2}-2ab+{b}^{2}$

$\tt{({x}^{2}-4)}^{2}$

•Rewrite $\tt{x}^{2}-4$ in the form $\tt{a}^{2}-{b}^{2}$

, where a=x and b=2.

$\tt{({x}^{2}-{2}^{2})}^{2}$

•Use Difference of Squares: $\tt{a}^{2}-{b}^{2}=(a+b)(a-b)$

$\tt{[(x+2)(x-2)]}^{2}$

•Use Multiplication Distributive Property: $\tt{(xy)}^{a}={x}^{a}{y}^{a}.$

$\boxed{\red{\tt{(x+2)}^{2}{(x-2)}^{2}}}$

hope it help you dear.

thanks.