plz any one can solve
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shivi14151:
let 1st is x and another is y, x=3y and x-y=26 then from eqn 1 and2 2y=26 ,y=13 ,x=39
Answers
Answered by
1
Let one of the nos be x.
so the 2nd no will be (x-26)
so acc to the given,
x= 3(x-26)
x = 3x - 78
3x-x= 78
x= 39
:. the nos are
x=39 ..... and
x-26= 39-26
= 13
so the 2nd no will be (x-26)
so acc to the given,
x= 3(x-26)
x = 3x - 78
3x-x= 78
x= 39
:. the nos are
x=39 ..... and
x-26= 39-26
= 13
mark me as the brainliest
☺☺☺
Yo, don't you think that your answer is incorrect?
The question says that the difference between two numbers... Hmm, you've got a mistake in reading the question.
why is it wrong!!????
yeah yeah... my mistake.. i m sry
but now i m ryt naa
Answered by
1
Heya!!
Here's your answer.
According to the question,
We have the difference between two numbers=26.
Also, one number is three times of the other.
So, let the first number be x and the other be 3x.
Therefore,
=>3x-x = 26
=>2x = 26
=>x = 26/2
=>x = 13.
Hence, the first number is x which will be 13 and the other number is 3x which will be 3×13=39.
Hope so that it did helped you and please mark it as brainiest, thank you!!
Here's your answer.
According to the question,
We have the difference between two numbers=26.
Also, one number is three times of the other.
So, let the first number be x and the other be 3x.
Therefore,
=>3x-x = 26
=>2x = 26
=>x = 26/2
=>x = 13.
Hence, the first number is x which will be 13 and the other number is 3x which will be 3×13=39.
Hope so that it did helped you and please mark it as brainiest, thank you!!
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