plz any one solve this problem
Attachments:
Answers
Answered by
0
Answer:
Step-by-step explanation:
hope it help you
Attachments:
Answered by
0
Step-by-step explanation:
IN TRIANGLE, ADE:-
BY THE PYTHAGORAS THEOREM,
(AD)^2 = (AE)^2+(DE)^2
(1.5)^2 = (1)^2+(DE)^2
2.25=1+(DE)^2
(DE)^2=2.25-1
(DE)^2=1.25
(DE)^2=0.25×5
(DE) =(0.25)^1/2×(5)^1/2
DE =0.5×(5)^1/2
IN TRIANGLES ADE AND ABC :-
ANGLE DAE= ANGLE BAC
DE IS PARALLEL TO BC
Similar questions