Question

plz anyone ans this question plz ​

Answer 1

Welcome to my answer

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Cos x/2 =+-1/√3

HERE X BELONGS TO 3RD QUADRANT.

BUT X/2 BELONGS TO 2ND QUADRANT.

THEN,

Sin x/2 =+√2/3

Tanx/2 = +-√2

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Hope this helps you

Mark as BRAINLIEST answer

Answer 2

Answer:

$\sqrt[3]{ y} = {y}^ \frac{1}{3}$

$\sqrt{y \sqrt{ {y}^{2} } } = y$

$\sqrt[3]{y \sqrt{ {y}^{2} } } = {y}^{ \frac{2}{3} }$

Baa