Plz anyone answer this question. It's urgent and no unnecessary answers plz! If u don't know ignore it!
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Omnamhashivay:
question of 10th class?
yup
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Hope u can do 3 yourself!
THIS IS THE ANSWER FROM MY SIDE
THIS IS THE ANSWER FROM MY SIDE
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just it helps in calculating image and object distances from it like in question 50-26=24 we get for solving
so, wht all things are given in the ques?
they haven't given the object and image distance??
assume the things are kept on co-ordinate graph then u will get
ohkay
mark as brianlist ansrr
please
mine iii is wrong it will be infinity
by mistake i wrote 18 instead of 12
writing 12 we get v=infinity
Answered by
1
Given,
Position of candle = 26 cm
Position of Convex lens = 50 cm
Position of screen = 74 cm
So,
(I) Object distance,
u = 50 - 26
= 24 cm
Image distance,
v = 74 - 50
= 24 cm
So, the image distance from lens is same to object distance.
Therefore,
Centre of curvature, c = 24 cm
Focal length,
f = 24/2
= 12 cm
(II) New position of candle = 38 cm
So,
Object distanc,
u = 50 - 38
= 12 cm
Focal length, f = 12 cm
Therefore, Object is at f.
Hence, image if formed at infinity.
(III) For ray diagram plz refer to the attachment.
Hope it may help you!!!!
All the best for tomorrow's exam!!!!!
Plz mark as brainlest!!!!!
Position of candle = 26 cm
Position of Convex lens = 50 cm
Position of screen = 74 cm
So,
(I) Object distance,
u = 50 - 26
= 24 cm
Image distance,
v = 74 - 50
= 24 cm
So, the image distance from lens is same to object distance.
Therefore,
Centre of curvature, c = 24 cm
Focal length,
f = 24/2
= 12 cm
(II) New position of candle = 38 cm
So,
Object distanc,
u = 50 - 38
= 12 cm
Focal length, f = 12 cm
Therefore, Object is at f.
Hence, image if formed at infinity.
(III) For ray diagram plz refer to the attachment.
Hope it may help you!!!!
All the best for tomorrow's exam!!!!!
Plz mark as brainlest!!!!!
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but isn't the position if the candle the image distance?
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