plz anyone answer this question. plzz....
Attachments:
rekharr1424:
hey gopika wlkm(bcoz u say thnks to me on my many answers)
Answers
Answered by
3
Answer:4√10 cm
Step-by-step explanation:
In ∆OAP
AP=12cm
OA=5cm
OP²=OA²+AP²
OP²=5²+12²
OP²=25+144=169
OP=13cm
Now, in ∆OBP
OP=13cm
OB=3cm
OP²=OB²+BP²
169=9+BP²
169-9=BP²
160=BP²
4√10=BP
I hope it helps u
Plzzz follow me...
Please mark it as BRAINLIEST.....
Plzzz like it...
And also accepty friei request...
Friend
AND thnk u for mark me as brainliest answer...
sorry my answer not me
then
thnk u
for mark it as brainliest
Answered by
6
Answer:4√10 cm
Step-by-step explanation:
In ∆OAP
AP=12cm
OA=5cm
OP²=OA²+AP²
OP²=5²+12²
OP²=25+144=169
OP=13cm
Now, in ∆OBP
OP=13cm
OB=3cm
OP²=OB²+BP²
169=9+BP²
169-9=BP²
160=BP²
4√10=BP
Similar questions