Question

PLZ ANYONE GIVE ME THE ANSWERS OF ACTIVE PASSIVE:​

Answer 1

Answer:

6) who was laughed at by you

7) a reward was promised by the headmaster

8) he exhibition was opened by the prime minister

9) the king was cheered by the people

10) the wall is being built by the Mason

11) geometry is taught to us by him.

if it helps please mark me the brainliest

Answer 2

Answer:

$\boxed{\bold{\pink{cos \alpha = \dfrac{9}{41} \: and \: cosec \alpha = \dfrac{41}{40} }}}$

Step-by-step explanation:

$\green{\bold{Given}}\longrightarrow \\ 9 \: cos \alpha + 40 \: sin \alpha = 41$

$\red{\bold{To \: find}}\longrightarrow \\ value \: of \: cos \alpha \: and \: cosec \alpha$

$\blue{\bold{Concept \: used }}\longrightarrow\\ 1) {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ 2) {sin}^{2} \alpha = 1 - {cos}^{2} \alpha \\ 3) {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ 4) \: cosec \alpha = \dfrac{1}{sin \alpha }$

$\pink{\bold{Solution}}\longrightarrow \\ 9cos \alpha + 40sin \alpha = 41$

$= > 40sin \alpha = 41 - 9cos \alpha$

$squaring \: both \: sides \: we \: get$

$= > {(40sin \alpha )}^{2} = {(41 - 9cos \alpha )}^{2}$

$= > 1600 {sin}^{2} \alpha = {(41)}^{2} + {(9cos \alpha) }^{2} - 2 \: (41) \: (9cos \alpha ) \\ = > 1600(1 - {sin}^{2} \alpha ) = 1681 + 81 {cos}^{2} \alpha - 738cos \alpha$

$= > 1600 - 1600 {cos}^{2} \alpha - 81 {cos}^{2} \alpha + 738cos \alpha - 1681 = 0 \\ = > - 1681 {cos}^{2} \alpha + 738cos \alpha + 81 = 0$

$= > 1681 {cos}^{2} \alpha - 738cos \alpha + 81 = 0 \\ = > {(41cos \alpha )}^{2} - 2 \: (41cos \alpha ) \: ( \: 9 \: ) + {(9)}^{2} = 0 \\ = > {(41cos \alpha - 9)}^{2} = 0 \\ taking \: square \: root \: of \: both \: sides \\ = > 41cos \alpha - 9 = 0 \\ = >41 cos \alpha = 9 \\ = >\pink{ cos \alpha = \dfrac{9}{41}} \\ now \\ {sin}^{2} \alpha = 1 - {cos}^{2} \alpha \\ = > sin \alpha = \sqrt{1 - {cos}^{2} \alpha } \\ = > sin \alpha = \sqrt{1 - {( \dfrac{9}{41}) }^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{1 - \dfrac{81}{1681} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ \dfrac{1681 - 81}{81} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ \dfrac{1600}{1681} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{40}{41}$

$now$

$cosec \alpha = \dfrac{1}{sin \alpha } \\ \\= > cosec \alpha = \dfrac{1}{ \dfrac{ 40}{41} } \\ \\ = >\pink{ cosec \alpha = \dfrac{41}{40}}$