Question

PLZ ANYONE GIVE ME THE ANSWERS OF ACTIVE PASSIVE​

Answer 1

a) the lights must be switched off at ten

b) the posters must not be sticked on the wall

c) A poem must be recited by you

d) you should get up in the morning

e) Let the work be set up by us

f) These books must be returned by Monday

g) The children must be told to keep quiet

h) Let the question be tried by me

i) I should not be disturbed

j) He must be told to leave the room

k)My orders must be carried

l) The poor must not be hated

m) Such mistake must not be made again

n) The truth should / must always be spoken

o) He must be helped

p)Let the situation be faced by him

q)The instructions must be listened carefully

MARK AS BRAINLIEST❤️

HOPE IT HELPED :)

Answer 2

Answer:

Answer:

$\boxed{\bold{\pink{cos \alpha = \dfrac{9}{41} \: and \: cosec \alpha = \dfrac{41}{40} }}}$

Step-by-step explanation:

$\green{\bold{Given}}\longrightarrow \\ 9 \: cos \alpha + 40 \: sin \alpha = 41$

$\red{\bold{To \: find}}\longrightarrow \\ value \: of \: cos \alpha \: and \: cosec \alpha$

$\blue{\bold{Concept \: used }}\longrightarrow\\ 1) {(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy \\ 2) {sin}^{2} \alpha = 1 - {cos}^{2} \alpha \\ 3) {(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ 4) \: cosec \alpha = \dfrac{1}{sin \alpha }$

$\pink{\bold{Solution}}\longrightarrow \\ 9cos \alpha + 40sin \alpha = 41$

$= > 40sin \alpha = 41 - 9cos \alpha$

$squaring \: both \: sides \: we \: get$

$= > {(40sin \alpha )}^{2} = {(41 - 9cos \alpha )}^{2}$

$= > 1600 {sin}^{2} \alpha = {(41)}^{2} + {(9cos \alpha) }^{2} - 2 \: (41) \: (9cos \alpha ) \\ = > 1600(1 - {sin}^{2} \alpha ) = 1681 + 81 {cos}^{2} \alpha - 738cos \alpha$

$= > 1600 - 1600 {cos}^{2} \alpha - 81 {cos}^{2} \alpha + 738cos \alpha - 1681 = 0 \\ = > - 1681 {cos}^{2} \alpha + 738cos \alpha + 81 = 0$

$= > 1681 {cos}^{2} \alpha - 738cos \alpha + 81 = 0 \\ = > {(41cos \alpha )}^{2} - 2 \: (41cos \alpha ) \: ( \: 9 \: ) + {(9)}^{2} = 0 \\ = > {(41cos \alpha - 9)}^{2} = 0 \\ taking \: square \: root \: of \: both \: sides \\ = > 41cos \alpha - 9 = 0 \\ = >41 cos \alpha = 9 \\ = >\pink{ cos \alpha = \dfrac{9}{41}} \\ now \\ {sin}^{2} \alpha = 1 - {cos}^{2} \alpha \\ = > sin \alpha = \sqrt{1 - {cos}^{2} \alpha } \\ = > sin \alpha = \sqrt{1 - {( \dfrac{9}{41}) }^{2} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{1 - \dfrac{81}{1681} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ \dfrac{1681 - 81}{81} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \sqrt{ \dfrac{1600}{1681} } \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \dfrac{40}{41}$

$now$

$cosec \alpha = \dfrac{1}{sin \alpha } \\ \\= > cosec \alpha = \dfrac{1}{ \dfrac{ 40}{41} } \\ \\ = >\pink{ cosec \alpha = \dfrac{41}{40}}$