Question

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Question





For an A.P , the first term is 14 and the last term is 212. If sum of these terms is 11300, find the number of terms and common difference and ​​

Answer 1

• Given : first term ,a = 14 ; last term, an = 212 ;

sum of n terms Sn = 11300;

• we know sum of n terms ,

Sn = n/2 × ( first term + last term)

so , 11300 = n/2 × ( 14 + 212 )

=> n = (2 × 11300) / ( 14 + 212 )

=> n = 100

• therefore number of terms of the AP is 100.

100th term = a + (100-1)×d ;

11300 = 14 + 99×d

d = 114.

• the common difference is 114.

Hope this helps you ✌️✌️☘️☘️