plz anyone let me know the steps to prove QR + SQ = QP + SR
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Answered by
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Property used; tangent drawn to a circle from same point are of same length.
AP = DP
CQ = DQ
CR = BR
AS = BS
Adding all the above equations we get,
AP+CQ+CR+AS = DP+DQ+BR+BS
(AP+AS)+(CQ+CR) = (DP+DQ)+(BR+BS)
SP+QR = QP+SR
Hence, proved.
Answered by
2
Answer:
let OA , OB , OC , OD be the radius of the circle.
and also OA = OB = OC = OD
Step-by-step explanation:
QR= QC + CR
also QC = OD
CR = OB
QR = OD + OB
similarly for the other sides,
since the radius are equal and sum of the sides is equal to 2R
therefore QR + SP = QP + SR
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